Question

In triangle ABC, right-angled at B, $AB=24cm,BC=7cm,sinA=\frac{7}{q}$, then $q$ is

Answer 1

If triangle ABC is right angled at vertex $B$; then $AC$ is the hypotenuse.
$\therefore$ By Pythagoras theorem, $AC=\sqrt{{AB}^2+{BC}^2}=\sqrt{{24}^2+7^2}=25cm\sin A=\frac{BC}{AC}=\frac{7}{25}$