In triangle ABC, right angled at B, Find the expressions of cos A , sin C, tan A and cot C.
A
AB/AC , BC/AC, BC/AB , AB/BC
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B
BC/AC , AB/AC, BC/AB , BC/AB
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C
AB/AC , AB/AC, BC/AB , BC/AB
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D
BC/AC , BC/AC, AB/BC , BC/AB
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Solution
The correct option is C AB/AC , AB/AC, BC/AB , BC/AB In Δ ABC, Sin C = Opposite/hypogenous = AB/AC cos A = adjacent/hypogenous = AB/AC tanA = Opposite/adjacent = BC/AB cot C = adjacent/Opposite = BC/AB