Question

In triangle $ABC$, right angled at $B$, find the expressions of $\tan A$ and $\cot C$​

• A. ,
• B. ,
• C. ,
• D. ,

Answer 1

The correct option is D. $\frac{BC}{AB},\frac{BC}{AB}$

In right $\Delta ABC$,

$\Rightarrow \tan A=\frac{\text{Perpendicular}}{\text{Base}}=\frac{BC}{AB}$

$\Rightarrow \cot C=\frac{\text{Base}}{\text{Perpendicular}}=\frac{BC}{AB}$