Question

In $△ABC$,right-angled at B.
If, $AB+AC=9cmandBC=3cm$

then find, ${\sin }^{2}C+{\cos }^{2}C$.

• A. 0
• B. 1
• C. -1
• D. 2

Answer 1

The correct option is B 1

As we know that

For any $\theta ,{\sin }^2\theta +{\cos }^2\theta =1$

So ${\sin }^{2}C+{\cos }^{2}C=1$