In ABC- right angled at C - AC -4 cm and - BAC -60- find the length of side BCA- 3 cmB- 4 -3 cmC- -3 cmD- 5 -3 cm

The correct option is B 4√(3) cm Since ∠ BAC =60^∘ ⇒ tan 60^∘ nbsp;= BC/AC = √(3) ⇒BC/4 = √(3) ⇒ BC = 4√(3) cm ...

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Standard X

Mathematics

Basics of Geometry

In ABC, right...

Question

In $△ A B C$ , right angled at C, AC=4cm and $∠ B A C = 60^{\circ}$ , find the length of side BC

$5 \sqrt{3}$ cm

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3 cm

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$4 \sqrt{3}$ cm

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$\sqrt{3}$ cm

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Solution

The correct option is C
$4 \sqrt{3}$ cm

Since $∠ B A C = 60^{\circ}$
$\Rightarrow t a n 60^{\circ} = \frac{B C}{A C} = \sqrt{3}$
$\Rightarrow \frac{B C}{4} = \sqrt{3}$
$\Rightarrow B C = 4 \sqrt{3}$ cm

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In △ABC, right angled at C, AC=4cm and ∠BAC=60∘, find the length of side BC

The correct option is C 4√3 cm Since ∠BAC=60∘ ⇒tan 60∘=BCAC=√3 ⇒BC4=√3 ⇒BC=4√3 cm

In $△ A B C$ , right angled at C, AC=4cm and $∠ B A C = 60^{\circ}$ , find the length of side BC

The correct option is C
$4 \sqrt{3}$ cm

Since $∠ B A C = 60^{\circ}$
$\Rightarrow t a n 60^{\circ} = \frac{B C}{A C} = \sqrt{3}$
$\Rightarrow \frac{B C}{4} = \sqrt{3}$
$\Rightarrow B C = 4 \sqrt{3}$ cm