In $△ A B C$ , right angles at $B,$ $A B = 24 c m, B C = 7 c m$ . Determine :
(i) $s i n A, c o s A$
(II) $s i n C, c o s B$

Open in App

Solution

$A C = \sqrt{{(24)}^{2} + {(7)}^{2}} = 25 (i) sin A = \frac{7}{25} cos A = \frac{24}{25} (i i) sin C = \frac{24}{25} cos B = 0$

Suggest Corrections

Similar questions

A B C

B, A B = 24 c m, B C = 7 c m

sin A, cos A

sin C, cos C

△ A B C

B, A B = 24 c m

B C = 7 c m

sin A, cos A

sin C, cos C

△ A B C

B

A B = 24 c m, B C = 7 c m

: (i) sin A, cos A, (i i) sin C, cos C

In ΔABC right angled at B, AB = 24 cm, BC = 7 cm. Determine

(i) sin A, cos A

(ii) sin C, cos C

Δ

Join BYJU'S Learning Program