In $△ A B C, R r (sin A + sin B + sin C)$ is equal
to

Δ

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2 s

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2 Δ

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s

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Solution

The correct option is A $Δ$
$R r (sin A + sin B + sin C) = R r (\frac{a}{2 R} + \frac{b}{2 R} + \frac{c}{2 R}) = \frac{Δ}{s} \times s = Δ$

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