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Question

In ABC,Rr(sinA+sinB+sinC) is equal
to


A
Δ
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B
2s
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C
2Δ
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D
s
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Solution

The correct option is A Δ
Rr(sinA+sinB+sinC)=Rr(a2R+b2R+c2R)=Δs×s=Δ

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