Question

In $△ABC$, seg $MN\parallel segBC$, If $BM=6,AN=5,AM=2$ then find $NC$.

Answer 1

In $\Delta$ABC

$\angle M=\angle B$

$\angle N=\angle C$

Also, sides AB & AM are in ratio.

So, $\Delta$AMN$\cong \Delta$ABC

Hence,

$\frac{6+2}{2}=\frac{x+5}{5}$

$x=15$.