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Area of a Triangle

In ABC, s...

Question

In $△ A B C$ , $s e g M N ∥ s e g B C$ , if $B M = 6$ , $A N = 5$ , $A M = 2$ , then find $N C$ .

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Solution

$\frac{A M}{A B} = \frac{A N}{A C}$

$\frac{2}{2 + 6} = \frac{5}{5 + x}$

$5 + x = 20$

$x = 15$

$∴ N C = 15$

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