In triangle ABC, side AB is produced to D so that BD = BC. If angle B = 60o and angle A = 70o, then
AD ≠ CD
AD = CD
AD > CD
AD < CD
In ΔABC, AB is produced to D so that BD=BC. if ∠B=60∘ and ∠A=70∘, prove that: (i) AD>CD (ii) AD>AC
In a triangle ABC, if AB = AC and AB is produced to D such that BD = BC, find ∠ACD:∠ADC.
In ΔABC, side AB is produced to D such that BD = BC. If ∠A=70∘ and ∠B=60∘, prove that (i) AD > CD (ii) AD > AC.