It is given that sin C = 35.
But, sin C = Opposite side(AB)Hypotenuse (AC).
Thus, we have AB = 3k and AC = 5k, where k is a natural number.
From Pythagoras' theorem, we have
BC = √(5k)2−(3k)2
= √25k2−9k2
= √16k2
= 4k cm
Now, the remaining ratios can be calculated as follows:
cos C = Adjacent sideHypotenuse= 45
tan C = Opposite sideAdjacent side= 34
cosec C = 1sin C= 53
sec C = 1cos C= 54