IN TRIANGLE ABC , tanA/2=5/6 , tanB/2=20/37 , tanC/2 = ???

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Solution

The above solution is correct.122/305 simplifies to 2/5. (Divide the numerator and denominator by 61).

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Similar questions

tan \frac{A}{2} = \frac{5}{6}, tan \frac{B}{2} = \frac{20}{37}

tan \frac{C}{2} = \frac{2}{5}

tan \frac{C}{2} = cot (\frac{A + B}{2})

A B C, tan \frac{A}{2} = 5 / 6, tan \frac{C}{2} = 2 / 5

In a triangle ABC, tan A + tan B +tan C = 6 and tan A $\times$ tan B = 2, then the value of tan A, tan B and tan C are

A B C

tan (A / 2) = 5 / 6

tan (B / 2) = 20 / 37

A B C, tan A + tan B + tan C = 6

tan A tan B = 2

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