In triangle ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then the value of AD is .

3.5 cm

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4 cm

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4.5 cm

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Solution

The correct option is C 4.5 cm
In a triangle, all the medians intersect at a single point and that point divides each in the ratio 2 : 1.

$Hence, A G : G D = 2 : 1$
Here, GD = 1.5 cm. So, AG will be 3 cm.
$\Rightarrow G D : A D = 1 : 3 \Rightarrow A D : G D = 3 : 1$

$So, \frac{A D}{G D} = \frac{3}{1}$

$\Rightarrow \frac{A D}{1.5}$ = 3

$\Rightarrow A D = 4.5 c m .$

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Similar questions

In $△ A B C,$ the medians $B E$ and $C F$ intersect at $G . A G D$ is a line meeting $B C$ at $D .$ If $G D$ is $1.5 c m,$ then $A D$ is equal to -

Δ

In $△$ ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then find the value of AD.

Δ A B C

B E

C F

G

A G D

B C

D

G D = 1.5 c m

A D

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