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Congruent Figures

In ABC, the m...

Question

In $△$ ABC, the medians BE and CF intersect at G. AG is a line when extended meets BC in D. If GD is 1.5 cm, then AD is equal to

2.5 cm

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3 cm

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4 cm

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4.5 cm

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Solution

The correct option is D
4.5 cm

AG : GD = 2 : 1 $\Rightarrow$ GD : AD = 1 : 3

$\Rightarrow$ AD : GD = 3 : 1

$\frac{A D}{G D}$ = $\frac{3}{1}$ $\Rightarrow$ $\frac{A D}{1.5}$ = 3 $\Rightarrow$ AD = 4.5 cm.

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