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Question

In ABC. AD the bisector of A intersects ¯BC in D. BD=......... .

A
BC×ABAB+AC
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B
BC×ABABAC
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C
BC×ABACAB
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D
BC×ABBC+AB
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Solution

The correct option is B BC×ABAB+AC
In ABC,
AD bisects A
ACAB=DCBD [ By angle bisector theorem ]

1+ACAB=1+DCBD

AB+ACAB=BD+DCBD

AB+ACAB=BCBD [ Since, BD+DC=BC ]

BD=AB×BCAB+AC

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