In triangle - ABC- 900- - CAB- x0- tan x0- 3-4 and BC- 15 cm- the measures of AB in cm

Given, ∠ ABC = 90^∘ , BC = 15 tan∠ CAB = 34 Now, tan∠ CAB = PB 34 = BCAB AB = 4 × 153 AB = 20 ...

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Standard XII

Mathematics

Angle between Two Lines

In triangle ...

Question

In triangle $∠ A B C = 90^{0}$ , $∠ C A B = x^{0}$ , $tan x^{0} = \frac{3}{4}$ and $B C = 15$ cm. the measures of $A B$ in cm

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Solution

Given, $∠ A B C = 90^{\circ}$ , $B C = 15$
$tan ∠ C A B = \frac{3}{4}$
Now, $tan ∠ C A B = \frac{P}{B}$
$\frac{3}{4} = \frac{B C}{A B}$
$A B = \frac{4 \times 15}{3}$
$A B = 20$

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In triangle∠ABC=900, ∠CAB=x0, tanx0=34 and BC=15 cm. the measures of AB in cm

Given, ∠ABC=90∘, BC=15tan∠CAB=34Now, tan∠CAB=PB34=BCABAB=4×153AB=20

In triangle $∠ A B C = 90^{0}$ , $∠ C A B = x^{0}$ , $tan x^{0} = \frac{3}{4}$ and $B C = 15$ cm. the measures of $A B$ in cm

Given, $∠ A B C = 90^{\circ}$ , $B C = 15$
$tan ∠ C A B = \frac{3}{4}$
Now, $tan ∠ C A B = \frac{P}{B}$
$\frac{3}{4} = \frac{B C}{A B}$
$A B = \frac{4 \times 15}{3}$
$A B = 20$