In $△$ BLE, BL = LE. What is the angle opposite to side BE if $∠$ LBE is equal to $45^{\circ}$

45º

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60º

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75º

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90º

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Solution

The correct option is D
90º

In $△$ BLE, BL = LE. So, $∠$ LBE = $∠$ LEB = $45^{\circ}$ (Given in the question)

Apply angle sum property of a triangle, $∠$ BLE + $∠$ LBE + $∠$ LEB = $180^{\circ}$

$∠$ BLE = $90^{\circ}$

Angle opposite to BE = $∠$ BLE = $90^{\circ}$

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In △BLE, BL = LE. What is the angle opposite to side BE if ∠LBE is equal to 45∘

The correct option is D 90º In △BLE, BL = LE. So, ∠LBE = ∠LEB = 45∘ (Given in the question) Apply angle sum property of a triangle, ∠BLE + ∠LBE + ∠LEB = 180∘ ∠BLE = 90∘ Angle opposite to BE = ∠BLE = 90∘

In $△$ BLE, BL = LE. What is the angle opposite to side BE if $∠$ LBE is equal to $45^{\circ}$

The correct option is D
90º

In $△$ BLE, BL = LE. So, $∠$ LBE = $∠$ LEB = $45^{\circ}$ (Given in the question)

Apply angle sum property of a triangle, $∠$ BLE + $∠$ LBE + $∠$ LEB = $180^{\circ}$

$∠$ BLE = $90^{\circ}$

Angle opposite to BE = $∠$ BLE = $90^{\circ}$