Question

In triangle $JKL,Jk=\sqrt{11},KL=\sqrt{7}andJL=\sqrt{4}.$

which angle will be ${90}^{\circ }$?

• A. $\angle J$
• B.
  $\angle J$
• C.
  $\angle L$
• D.
  None of these

Answer 1

The correct option is C

$\angle L$
In triangle JKL,

$JK=\sqrt{11},KL=\sqrt{7},JL=\sqrt{4}(\sqrt{11}{)}^2=11,(\sqrt{7}{)}^2=7,(\sqrt{4}{)}^2=4$

Apply Pythagoras Theorem

That is ,

$(\sqrt{11}{)}^2=(\sqrt{7}{)}^2+(\sqrt{4}{)}^2$

Hence, according to the coverse of pythagoras theorem.
Triangle JKL is right angled triangle.

Here, the longest side of the triangle is JK, which is opposite to angle L.

Hence, $\angle L={90}^{\circ }$

Hence, the given $\Delta JKL$ is a right angled triangle, having $\angle L={90}^{\circ }.$

So, option c is correct.