Question

In $△$ LAW, $\angle LAW={90}^o$, $\angle LNA={90}^o$, LW = 26 cm, LN = 6 cm and AN = 8 cm. Calculate the length of WA.

Answer 1

In $\Delta LNA$,

Use Pythagoras Theorem:

$(LN{)}^2+(NA{)}^2=(LA{)}^2$

$⟹LA=10cm$

In $\Delta LWA$,

Use Pythagoras Theorem:

$(AW{)}^2+(LA{)}^2=(LW{)}^2$

$⟹AW=\sqrt{(26cm{)}^2-(10cm{)}^2}$

$⟹AW=24cm$