Question

In $△PQR,\angle PQR={90}^{\circ }$ if $PR=15$ and $PQ=9cm$ find $QR$

Answer 1

In $△PQR,$

$\angle PQR={90}^{\circ }$

$PR=15$

$PQ=9cm$

By Pytagorous therm

$P{R}^2=Q{R}^2+P{Q}^2{15}^2=9^2+Q{R}^{2}225=81+Q{R}^{2}Q{R}^2=225-81QR=\sqrt{144}QR=12cm$