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Question

In XYZ,XY=4 cm,YZ=6 cm,XZ=5 cm. If ΔXYZΔPQR and PQ=8 cm, then find the lengths of remaining sides of PQR.

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Solution

XYZPQR [Given]
XYPQ=YZQR=XZPR [Corresponding sides of similar triangles]
48=6QR=5PR
Now, 48=6QR
QR=6×84
QR=12 cm
PR=5×84
PR=10 cm
QR=12 cm,PR=10 cm

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