In OAB- if OA-a-OB-b-L is mid point of OA and M is a point on OB such that OM-MB-2-1- If P is the mid point of LM- then AP-

Given : L is mid point of OA nbsp; ⇒OL=a2 OM:MB=2:1. P.V. of M=2b3 Since P is mid point of LM P.V. of P=a2+2b32 AP=a4+b3 a ∴AP= 3a4+b3 ...

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In OAB, if OA...

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In $△ O A B,$ if $- - \to O A = \to a, - - \to O B = \to b, L$ is mid point of $- - \to O A$ and $M$ is a point on $- - \to O B$ such that $- - \to O M : - - \to M B = 2 : 1.$ If $P$ is the mid point of $- - \to L M,$ then $- - \to A P =$

\frac{\to a}{4} + \frac{4 \to b}{3}

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- \frac{3 \to a}{4} - \frac{4 \to b}{3}

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- \frac{3 \to a}{4} + \frac{\to b}{3}

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\frac{\to a}{4} + \frac{\to b}{3}

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