In $△ P Q R, P Q = 10 c m, Q R = 12 c m, P R$ triangle. $8 c m$ . Find out the greatest and the smallest angle of the triangle.

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Solution

In $△ P Q R$ , $P Q = 10 c m, Q R = 12 c m, P R = 8 c m$ [Given] Since, $12 > 10 > 8$ $∴ Q R > P Q > P R$ $∴ ∠ Q P R > ∠ P R Q > P Q R [$ Angle opposite to greater side is greater] $∴$ In $△ P Q R, ∠ Q P R$ is the greatest angle and $∠ P Q R$ is the smallest angle.

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