In triangle PQR, A and B are points on PQ, PR such that PA=4, PB=3, AQ = 8, BR = 6, then AB and QR are:
Intersecting lines
Parallel lines
Same line
PQR is a triangle in which PQ = PR and S is any point on the side PQ. Through S, a line is drawn parallel to QR and intersecting PR at T. Prove that PS = PT.