Question

In $△PQR,\angle ={90}^o,PQ=12cm,QR=5cm$ and $QS$ is a median. Find $l\left(PS\right)$

Answer 1

R.E.F image

In $△$ PQS

$PQ=12cm$

$QS=\frac{QR}{2}=\frac{5}{2}=2.5cm$

using Pythagoras therm,

$P{S}^2=P{Q}^2+Q{S}^2$

$P{S}^2={12}^2+(2.5{)}^2$

$=144+6.25$

$=150.25$

PS = $\sqrt{150.25}$

$=12.25cm$