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Question

In PQR, P=300,Q=600,R=900 and PQ=10, then find PR and QR.

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Solution

In PQR, P=300,Q=600,R=900 and PQ=10
sin60=PRPQ ( sinθ=PerpendicularHypotenuse)
32=PR10
PR=53 cm
cos60=QRPQ ( cosθ=BaseHypotenuse)
12=QR10
QR=5 cm

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