Question

In $△PQR,\angle P$ is right angle. $A,B$ are mid points of $RP$ and $RQ$.

$RP=3,RQ=5$. Find length of $AB$.

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$2$

A & B are mid points
$\therefore AB=\frac{1}{2}PQ$
In $△PQR,\angle P$ in right
$\therefore$ By applying pythagoram then,
we can get PQ
$PQ=\sqrt{R{Q}^2-P{R}^2}=\sqrt{5^2-3^2}=\sqrt{25-9}$
$PQ=\sqrt{16}$
$PQ=4$
$\therefore AB=\frac{1}{2}PQ$
$AB=\frac{1}{2}\times 4$
$AB=2$