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Question

In PQR, E and F are points on the sides PQ and PR respectively. verify EF || QR. PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm, FR = 2.4 cm.

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Solution

The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that PE=3.9 cm, EQ=3 cm, PF=3.6 cm and FR=2.4 cm.

Using the basic proportionality theorem, we have

PEEQ=3.93=1.3PFFR=3.62.4=1.5

Since PEEQPFFR

Hence, EF is not parallel to QR.


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