Question

In $△PQR,PQ=PR$ and $m\angle P={40}^o$ then $m\angle Q=.$

Answer 1

Given that $PQ=PR$ then $\angle R=\angle Q=x$

$\angle P+\angle Q+\angle R={180}^{\circ }$

$x+x+{40}^{\circ }={180}^{\circ }$

$x={70}^{\circ }.$

$\angle R=\angle Q={70}^{\circ }.$