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In triangle P...

Question

In triangle PQR, Q > angle R; PA is the bisector of angle QPR ; PM IS perpendicular to PR .prove that angle APM=1/2(angle Q - angle R).

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Solution

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Similar questions

In ∆PQR, PR > PQ, PA is the bisector of angle P and PM is perpendicular to QR. Prove that angle APM = 1/2 ( angle Q - angle R).

∠ Q > ∠ R

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∠ A P M = 1 / 2 (∠ Q - ∠ R)

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∠ Q > ∠ R

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∠ Q P R

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∠ A P M = \frac{1}{2} (∠ Q - ∠ R)

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∠ A P M = \frac{1}{2} (∠ Q - ∠ R)

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∠ A P M = \frac{1}{2} (∠ Q - ∠ R)

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