Question

In $△PQR,ST\parallel QR$ and $\frac{PS}{SQ}=\frac{3}{5}$ if $PR=6$cm find $PT$

Answer 1

In $△PQR,$ we have $ST\parallel QR$

By Basic proportionality theorem,

$\frac{PS}{SQ}=\frac{PT}{TR}$

$\Rightarrow \frac{PS}{SQ}=\frac{PT}{PR-PT}$

$\Rightarrow \frac{3}{5}=\frac{PT}{6-PT}$

$\Rightarrow 18-3PT=5PT$

$\Rightarrow 8PT=18$

$\Rightarrow PT=\frac{18}{8}=2.25$cm