Question

In triangle $\text{PQR}$, $\angle Q={90}^{\circ }$,
find: i $\text{PR},\text{if PQ}=8cm\text{and QR}=6cm$

Answer 1

Step: Applying Pythagoras theorem to find length of hypotenuse

Since $△\text{PQR}$ is right angled triangle with vertex Q.
Given, $PQ=8cm;QR=6cm$
According to Pythagoras theorem,
${\text{Hypotenuse}}^2={\text{Perpendicular}}^2+{\text{base}}^2$
$(PR{)}^2=(PQ{)}^2+(QE{)}^2$
$(PR{)}^2=(8{)}^2+(6{)}^2$
$(PR{)}^2=64+36$
$PR=\sqrt{100}$
$PR=10cm$
Hence, $PR=10cm$