Question

In triangle $\text{PQR}$, $\angle Q={90}^{\circ }$,
find: ii $\text{PQ},\text{if PR}=34cm\text{and QR}=30cm$

Answer 1

Step: Applying Pythagoras theorem to find length of perpendicular

Since $△\text{PQR}$ is right angled triangle with vertex Q.
Given, $PR=34cm;QR=30cm$
According to Pythagoras theorem,
${\text{Hypotenuse}}^2={\text{Perpendicular}}^2+{\text{base}}^2$
$(PR{)}^2=(PQ{)}^2+(QR{)}^2$
$(34{)}^2=(PQ{)}^2+(30{)}^2$
$(PQ{)}^2=1156-900$
$PQ=\sqrt{256}$
$PQ=16cm$
Hence, $PQ=16cm$