In triangle XYZ, XY = 5 cm, YZ = 4 cm and XZ = 6 cm. Find the largest and the smallest angle. Justify?

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Solution

Angles will be proportional to the length of the opposite side.
$∠ X : ∠ Y : ∠ Z = 4 : 6 : 5$
$4 k + 6 k + 5 k = 180$
$15 k = 180$
K = $180^{\circ}$
K = $12^{\circ}$
Smallest angle $= 4 k = 48^{\circ}$
Largest angle $= 6 k = 72^{\circ}$

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In triangle XYZ, XY = 5 cm, YZ = 4 cm and XZ = 6 cm. Find the largest and the smallest angle. Justify?

Angles will be proportional to the length of the opposite side. ∠X:∠Y:∠Z=4:6:5 4k+6k+5k=180 15k=180 K = 180∘ K = 12∘ Smallest angle =4k=48∘ Largest angle =6k=72∘

Angles will be proportional to the length of the opposite side.
$∠ X : ∠ Y : ∠ Z = 4 : 6 : 5$
$4 k + 6 k + 5 k = 180$
$15 k = 180$
K = $180^{\circ}$
K = $12^{\circ}$
Smallest angle $= 4 k = 48^{\circ}$
Largest angle $= 6 k = 72^{\circ}$