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Question

In triangles ABC and DEF, addition to the markings, AF = CD and AB || DE. Which of the following methods can NOT be used to prove the triangles congruent?


A

SSS

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B

SAS

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C

AAS

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D

RHS

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Solution

The correct option is A

SSS


AB || DE. So, BAC = EDF and BCA = EFD (FE || BC, line segments perpendicular to parallel lines are parallel).

Also, it's given that AF = CD

which implies, AF + FC = CD + FC

which is, AC = DF.

So, the triangles can be proven congruent based on SAS, AAS and RHS congruency criteria but not SSS.


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