In triangles ABC and PQR, if $∠ A = ∠ R .$

$∠ B = ∠ P a n d A B = R P, then which one of the following congruence condition applies:$

SAS

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ASA

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SSS

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RHS

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Solution

The correct option is B
ASA

In $(b) Δ A B C a n d Δ P Q R,$

$∠ A = ∠ R$

$∠ B = ∠ P$

$A B = R P$

$∴ Δ A B C ≅ Δ P Q R (ASA axiom)$

Suggest Corrections

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