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Question

In two construction companies A and B, the average weekly wages in rupees and the standard deviations are as follows:
CompanyAverage of wages (in Rs)S.D of wages in (Rs)
A34506.21
B28504.56
Determine which factory has greater variability in individual wages?

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Solution

COMPANY A
¯xA=3450
σA=6.21
CVA=(σA¯xA)×100
CVA=0.18

COMPANY B
¯xB=2850
σB=4.56
CVB=(σB¯xB)×100
CVB=0.16
We know variability of a firm depends upon coefficient of variation.
Higher the coefficient of variation, higher the variability.
CVA>CVB
Company B has greater variability in individual wages

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