In two-digit number, first digit is four times of second digit. Adding this to the new number formed by reversing the digits, $110$ is obtained. Find the numbers .

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Solution

Let the no be 10y+x
y=4x--(1)
10y+x+10x+y=110
11x+11y=110
x+y=10--(2)
From 1 and 2x=2 and y=8
Therefore the no is 10(8)+2=82

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In two-digit number, first digit is four times of second digit. Adding this to the new number formed by reversing the digits, 110 is obtained. Find the numbers .

Let the no be 10y+xy=4x--(1)10y+x+10x+y=11011x+11y=110x+y=10--(2)From 1 and 2x=2 and y=8Therefore the no is 10(8)+2=82

In two-digit number, first digit is four times of second digit. Adding this to the new number formed by reversing the digits, $110$ is obtained. Find the numbers .

Let the no be 10y+x
y=4x--(1)
10y+x+10x+y=110
11x+11y=110
x+y=10--(2)
From 1 and 2x=2 and y=8
Therefore the no is 10(8)+2=82