In two elements- Z1M1A and Z2M2B-M1-M2 and Z1- Z2 but M1- Z1 - M2-Z2 -A and B are-

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In two elemen...

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In two elements, $_{Z_{1}}^{M_{1}} A a n d_{Z_{2}}^{M_{2}} B, M_{1} \neq M_{2} a n d Z_{1} \neq Z_{2} but (M_{1} - Z_{1}) = (M_{2} - Z_{2}) .$
A and B are:

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_{Z_{1}}^{M_{1}} A a n d_{Z_{2}}^{M_{2}} B, M_{1} \neq M_{2} a n d Z_{1} \neq Z_{2} but (M_{1} - Z_{1}) = (M_{2} - Z_{2}) .

_{Z_{1}}^{M_{1}} A a n d_{Z_{2}}^{M_{2}} B, M_{1} \neq M_{2} a n d Z_{1} \neq Z_{2} but (M_{1} - Z_{1}) = (M_{2} - Z_{2}) .

z_{1} & z_{2}

a r g (\frac{z_{1} + z_{2}}{z_{1} - z_{2}}) = \frac{π}{2}

| z_{1} + z_{2} | \neq | z_{1} - z_{2} |

z_{1}, z_{2}, z_{1} + z_{2}

z_{1}

z_{2}

z_{1} \neq z_{2}

| z_{1} | = | z_{2} |

\frac{z_{1} + z_{2}}{z_{1} - z_{2}}

z_{1}

z_{2}

| z_{1} | + | z_{2} | = ∣ ∣ ∣ \frac{z_{1} + z_{2}}{2} + \sqrt{z_{1} z_{2}} ∣ ∣ ∣ + ∣ ∣ ∣ \frac{z_{1} + z_{2}}{2} - \sqrt{z_{1} z_{2}} ∣ ∣ ∣

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