Question

In two successive throws of a pair of dice, determine the probability of getting a total of 8 each time.

Answer 1

Let A denote the event of getting a total of 8 in first throw and B be the event of getting a total of 8 in second throw. Then,

$P\left(A\right)=\frac{5}{36}$ and $P\left(B\right)=\frac{5}{36}$

Therefore,

Required probability = $P(A\cap B)$

$=P\left(A\right)P\left(B\right)=\frac{5}{36}\times \frac{5}{36}=\frac{25}{1296}$