Question

In two triangles, the ratio of their areas is $4:3$ and that of their heights is $3:4,$ Find the ratio of their bases.

Answer 1

$\frac{AreaofTriangle1}{AreaofTriangle2}$=$\frac{\frac{1}{2}\times \left(Bas{e}_1\right(Height{)}_1)}{\frac{1}{2}\left(Base{)}_2\right(Height{)}_2}$

$\frac{4}{3}$=$\frac{(Base{)}_1}{(Base{)}_2}\times \frac{3}{4}$ $(\because$ given data)

$\frac{(Base{)}_1}{(Base{)}_2}=\frac{16}{9}$