In $P h - C H (O H) {C H}_{3} S p e c i f i c r o t a i o n = + 50^{o} S O {C l}_{2} - --- \to P h C l | C l - {C H}_{3}$
the reaction is carried out in the presence of pyridine. Which of the following mechanisms does it follow?

{S_{N}}^{1}

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S_{N} 2

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S_{N} i

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E_{2}

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Solution

The correct option is B $S_{N} 2$
The reaction proceeds through $S N^{2}$ mechanism when it is carried out in presence of pyridine. The $- O H$ group of optically active substrate is replaced with $- C l$ atom with inversion in configuration.

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P h - C H (O H) {C H}_{3} S p e c i f i c r o t a i o n = + 50^{o} S O {C l}_{2} - --- \to P h C l | C l - {C H}_{3}

P h - C H (O H) {C H}_{3} Specific Rotaion = + 50^{o} S O {C l}_{2} - --- \to P h C l | C l - {C H}_{3}

P h - C H (O H) {C H}_{3} S p e c i f i c r o t a t i o n = + 50^{o} S O {C l}_{2} - --- \to P h C H | C l - {C H}_{3}

How to know whether a reaction is following Sn1,Sn2,Sn ar,E1,E2 or E1cb mechanism?

please mention a way which does have any exceptions.

S n {C l}_{2}

S n {C l}_{2} + {C l}_{2} ⟶ S n {C l}_{4}

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