CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In uniform electric field E=10 N/C as shown in figure. The potential difference, VAVB and VBVC respectively


A
10 V, 20 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10 V, 20 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10 V, 20 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10 V, 20 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 10 V, 20 V
Given,
Intensity of electric field, E=10 N\C

Since, electric field is directed from higher electric potential to lower electric potential means electric potential decreases in the direction of electric field.

Thus, VB>VA, So, (VAVB) will be negative.

From figure, the distance dAB between the points A and B along E,

dAB=2cos60=1 m

Using the relation, VAVB=EdAB
we get,

VAVB=(10)(1)

VAVB=10 V

Similarly, for uniform E

VB>VC, So (VBVC) will be positive.

From figure, the distance dBC between the points B and C along E,

dBC=2.0 m

Using the relation, VBVC=EdBC
we get,

VBVC=(10)(2)

VBVC=20 V

Hence, option (b) is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Field Due to Charge Distributions - Approach
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon