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Question

# In uniform electric field E=10 N/C as shown in figure. The potential difference, VAâˆ’VB and VBâˆ’VC respectively

A
10 V, 20 V
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B
10 V, 20 V
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C
10 V, 20 V
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D
10 V, 20 V
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Solution

## The correct option is B −10 V, 20 VGiven, Intensity of electric field, E=10 N\C Since, electric field is directed from higher electric potential to lower electric potential means electric potential decreases in the direction of electric field. Thus, VB>VA, So, (VA−VB) will be negative. From figure, the distance dAB between the points A and B along E, dAB=2cos60∘=1 m Using the relation, VA−VB=−EdAB we get, VA−VB=(−10)(1) ⇒VA−VB=−10 V Similarly, for uniform →E VB>VC, So (VB−VC) will be positive. From figure, the distance dBC between the points B and C along E, dBC=2.0 m Using the relation, VB−VC=EdBC we get, VB−VC=(10)(2) ∴VB−VC=20 V Hence, option (b) is correct answer.

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