Question

In $△$ABC, $\angle$ABC = 90${}^{\circ }$, $\angle$BAC = 45${}^{\circ }$ and $\angle$ACB = 45${}^{\circ }$. What is this triangle called?

• A. Right angled triangle
• B. Isosceles triangle
• C. 90^o triangle
• D. Right angled Isosceles triangle

Answer 1

The correct option is D

Right angled Isosceles triangle

In a right-angled isosceles triangle, one angle is right angle and the rest two are acute and equal i.e. 45${}^{\circ }$.