In vector diagram shown in fig- R is the resultant of vectors A and B- If R - B -2- the value of angle - isA- 30-B- 45-C- 60-D- 75-

The correct option is B It follows from figure that B^2 = R^2 + A^2 = B^2/2 + A^2 or A = B/√(2). Thus R = A. Hence θ = 45^∘. Therefore the correct choice is ...

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Standard XII

Physics

Work Done as Dot Product

In vector dia...

Question

In vector diagram shown in fig. R is the resultant of vectors A and B.
If R = $\frac{B}{\sqrt{2}}$ , the value of angle $θ$ is

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Solution

The correct option is B
It follows from figure that $B^{2} = R^{2} + A^{2} = \frac{B^{2}}{2} + A^{2} o r A = \frac{B}{\sqrt{2}} .$
Thus R = A. Hence $θ = 45^{\circ}$ .
Therefore the correct choice is (b)

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In vector diagram shown in fig. R is the resultant of vectors A and B. If R = B√2, the value of angle θ is

The correct option is B It follows from figure that B2=R2+A2=B22+A2orA=B√2. Thus R = A. Hence θ=45∘. Therefore the correct choice is (b)

In vector diagram shown in fig. R is the resultant of vectors A and B.
If R = $\frac{B}{\sqrt{2}}$ , the value of angle $θ$ is

The correct option is B
It follows from figure that $B^{2} = R^{2} + A^{2} = \frac{B^{2}}{2} + A^{2} o r A = \frac{B}{\sqrt{2}} .$
Thus R = A. Hence $θ = 45^{\circ}$ .
Therefore the correct choice is (b)