Question

In what ratio a grocer mix two varieties of tea worth Rs. 60 per kg and Rs. 65 per kg so that by selling mixture at Rs. 68.20 kg he may gain 10%?

• A. 3:2
• B. 3:4
• C. 3:5
• D. 4:5

Answer 1

The correct option is A

3:2

SP of 1 kg of mixture=Rs. 68.20
Gain=10%
CP of 1 kg mixture =Rs. $(\frac{100}{110}\times 68.20)=Rs.62$
Let grocer mixed x kg of tea worth Rs. 60 per kg to y kg of tea worth Rs. 65 per kg.
Cost of (x+y) kg of tea= Rs.(60x+65y)
$\because$ Cost of 1 kg of mixture= Rs. 62
$\therefore$ Cost of (x+y) kg of mixture =Rs. 62(x+y)
So, 62(x+y)=60x+65y
62x+62y=60x+65y
2x=3y
$\frac{x}{y}=\frac{3}{2}$
Required ratio is 3:2.