Question

In what ratio does x-axis divides line segment joining points (2, -3) and (5,6)

• A. 1:2
• B. 2:1
• C. 2:-1
• D. -1: 2

Answer 1

The correct option is A 1:2

Solution :-

Given x-axis divide the segment joining points

$(2,-3)$ and $(5,6)$

Let the ratio be $k:1$

then x = $\frac{m_1{x}_2+m_2{x}_1}{m_1+m_2}$

$y=\frac{m_1{y}_2+m_2{y}_1}{m_1+m_2}=0$

$\Rightarrow \frac{6k-3}{k+1}=0$

$\Rightarrow 6k=3$

$\Rightarrow k=\frac{1}{2}$

the ratio is $1:2$