Question

In what ratio is the joining the points
$(2,-3)$ and $(5,6)$ divided by the $x-$axis.

Answer 1

Given points $(2,-3),(5,6)$

Let x-axis divide it in ratio k.

Now k-coordinate is zero

$0=\frac{6k-3\left(1\right)}{k+1}$

$6k=3$

$k=\frac{1}{2}$

$\therefore$ x-axis divide it in ratio $1:2$.