Question

In what ratio is the line segment joining the points $(-3,2)$ and $(6,1)$ is divided by $y$-axis ?

• A. $1:3$
• B. $2:1$
• C. $1:2$
• D. $3:1$

Answer 1

The correct option is C $1:2$

Given the points A(-3, 2) and B (6, 1)

$(x_1,y_1)(x_2,y_2)$

Let the coordinate of points $(0,y)$ divide the given points in the ratio m:n

We can use section formula to find the coordinates of $(0,y)$

$⟹(0,y)=(\frac{m{x}_2+n{x}_1}{m+n},\frac{m{y}_2+n{y}_1}{m+n})$

$⟹(\frac{6m-3n}{m+n},\frac{m+2n}{m+n})=(0,y)$

Equating the x- axis co-ordinates we get,

$\therefore \frac{6m-3n}{m+n}=0\therefore 6m=3ni.e,\frac{m}{n}=\frac{1}{2}$

$\therefore$ Required ratio = $1:2$