CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Wave Equation

In what time ...

Question

In what time after its motion begins, will a particle oscillating according to the equation $x = 5 c o s 0.2 π t$ move from the mean position to maximum displacement position?

Open in App

Solution

At mean position,
$x = 0$
$5 cos (0.2 π t_{1}) = 0$
$0.2 π t_{1} = π / 2$
$t_{1} = 2.5 s$

At extreme position,
$x = - 5$
$5 cos (.2 π t_{2}) = - 5$
$.2 π t_{2} = π$
$t_{2} = 5 s$

Time taken is $2.5 s$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A particle is oscillating according to the equation

X = 7 cos 0.5 π t

T

is in second. The point moves from the position of equilibrium to maximum displacement in time.

Q. Oscillation of a particle is prescribed by the equation

x = 3 cos 0.25 π t

where t is the time in seconds. Then time taken by the particle to move from position of equilibrium to maximum displacement is

Q. The time taken by a particle executing simple harmonic motion of time period T to move from the mean position to half the maximum displacement is

Q. A particle is executing simple harmonic motion. Its displacement is given by

x = 5 sin π t

x

cm

t

in seconds. How long will the particle take to move from the position of equilibrium to the position of maximum displacement ?

Q. The time taken by a particle executing simple harmonic motion to move from the mean position to

(1 / 4)^{t h}

of the maximum displacement is

1 s

. Calculate the angular frequency of oscillation.

[{sin}^{- 1} (1 / 4) = 0.252]

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Building a Wave

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon